16x^2+9x^2=139,7^2

Solution for 16x^2+9x^2=139,7^2 equation:

16x^2+9x^2=139.7^2

We move all terms to the left:

16x^2+9x^2-(139.7^2)=0

We add all the numbers together, and all the variables

25x^2-19516.09=0

a = 25; b = 0; c = -19516.09;
Δ = b2-4ac
Δ = 02-4·25·(-19516.09)
Δ = 1951609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1951609}=1397$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1397}{2*25}=\frac{-1397}{50}
=-27+47/50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1397}{2*25}=\frac{1397}{50}
=27+47/50
$